A diver running 1.7 m/s dives out horizontally from the edge of a vertical cliff and reaches the water?

A diver running 1.7 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 2.9 s later. How high was the cliff and how far from its base did the diver hit the water?
____m (cliff)
____m (distance from base)

From y = 1/2*g*t^2 you can determine the height = 1/2*9.8*2.9^2 = 41.2m

So his distance from the edge is x = vx*t = 1.7m/s*2.9s = 4.93m

The highest scored dive in cliff diving

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