Diving North East

I have questions. help.?
1. The summit of a mountain, 2450m above the base camp, is measured on a map 4580m horizontally from the camp on a direction 32.4 ° west of north. What are the components of displacement vector field to the top? What is its magnitude? Choose the x axis east, north and y-axis above. 2. A diver running 1.8m / s dives horizontally from the edge of a vertical cliff and 3.0s later water gets below. What high is the cliff, and how far from his base the diver hit the water?
# 1 – Difficult to explain, just carefully remove the xyz coordinates and use some basic trigonometry. I get: X =- 2454m and 3867 m 2450 m = Z = # 2 – Fixed horizontal and verticle pieces of the problem independently, and assumes no air resistance anywhere. Part verticle: Since the runs "horizontally", assume its vertical velocity is initially zero. Then falls due to gravity (only) for 3 seconds. The vertical distance covered during that time can be found at: X = 1 / 2 * g * t ^ 2 + Vo * t + Xo (Vo = Xo = 0), so X = 1 / 2 * 9.8 * 3 ^ 2 = 44.1m (height of cliff) to the horizontal distance, assuming his horizontal speed (1.8 m / s) is constant (no air resistant to arrest). He travels horizontally at this speed for 3s b4 it hits the water, so that X = V * t = 1.8 * 3 = 5.4m.
Coast Guard Air Station Corpus Christi Rescues Diver